Question

if pth term of an ap is 1/q and qth term is 1/p then find d​

Answer 1

Answer:

sorry I cant help you

Step-by-step explanation:

Answer 2

Answer:

d (common difference) = 1/pq

Step-by-step explanation:

Let 'a' be the first term and 'd' be the common difference of the A. P. Then,

Given,

pth term = 1/q

a + (p - 1)d = 1/q

aq + (pq - q)d = 1  --- (1)

Similarly, 

 ap + (pq - p)d = 1  --- (2)

From (1) and (2), we get

aq + (pq - q)d = ap + (pq - p)d 

aq - ap = d[pq - p - pq + q]

a(q - p) = d(q - p)

Therefore, a = d

Equation (1) becomes,

dq + pqd - dq = 1  

d = 1/pq

Hence a = 1/pq