if pth term of an ap is 1/q and qth term is 1/p then find d
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Answered by
7
Answer:
d (common difference) = 1/pq
Step-by-step explanation:
Let 'a' be the first term and 'd' be the common difference of the A. P. Then,
Given,
pth term = 1/q
a + (p - 1)d = 1/q
aq + (pq - q)d = 1 --- (1)
Similarly,
ap + (pq - p)d = 1 --- (2)
From (1) and (2), we get
aq + (pq - q)d = ap + (pq - p)d
aq - ap = d[pq - p - pq + q]
a(q - p) = d(q - p)
Therefore, a = d
Equation (1) becomes,
dq + pqd - dq = 1
d = 1/pq
Hence a = 1/pq
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