if pth term of an AP is 1/q,qth term is 1/p ,show that pqth term is 1.
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Hallo dear ^ ^
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Pth = 1/q => a+( P - 1 )d = 1/q -------( 1 )
qth = 1/p => a+( q - 1 ) d = 1/p -------( 2 )
subtracting equation ( 1 ) and ( 2 )
( P - q ) d = 1/q - 1/p
( P - q ) d = ( P - q ) / pq
[ d = 1 / Pq ]
putting the value of d in equation ( 1 )
a + ( P - 1 ) 1 / pq = 1/q
a + 1/q - 1/pq = 1/q
a = 1/q + 1/pq - 1/q
[ a = 1 / pq ]
Now , we have to prove pqth term is 1
so ,
pqth = a+( pq - 1 ) d
= 1/pq + ( pq - 1 ) × 1 / pq
= 1/pq + 1 - 1 / pq
= 1
hence , pqth term is 1 .
~~~~~~~~~~~~ proved ~~~~~~~~~~~~~
# mark it brainlist answer.
# thank you ^ ^
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