if pth term of an ap is Q and qth term of an ap is P then show that its 10th term is P + Q - n
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Let the pth term be (a + (p-1)*d) [where d is the common difference and a is the first term of the arithmetic progression].
Similarly, the qth term will be (a + (q-1)*d)
Now, using the given information:
a + (p - 1)*d = q ....(1)
a + (q - 1)*d = p ....(2)
Substracting (2) from (1), we get d = -1
Adding (1) and (2) and putting d = -1, we get
a = p + q - 1
As above, the nth term will be (a + (n-1)*d)
Substituting the values of a and d in this, we get
p + q - 1 + (n - 1)*(-1)
= p + q - 1 - n + 1
= p + q - n
Hence, we get that the nth term of the series is (p + q - n).
AND PLS CORRECT YOUR. QUESTION
WE HAVE NOT FIND 10TH TERM HERE, WE HAVE TO FIND NTH TERM TO ROBE IT.
HOPE IT IS HELPFUL TO YOU,
PLS MARK IT AS BRAINLIEST!!!!
Let the pth term be (a + (p-1)*d) [where d is the common difference and a is the first term of the arithmetic progression].
Similarly, the qth term will be (a + (q-1)*d)
Now, using the given information:
a + (p - 1)*d = q ....(1)
a + (q - 1)*d = p ....(2)
Substracting (2) from (1), we get d = -1
Adding (1) and (2) and putting d = -1, we get
a = p + q - 1
As above, the nth term will be (a + (n-1)*d)
Substituting the values of a and d in this, we get
p + q - 1 + (n - 1)*(-1)
= p + q - 1 - n + 1
= p + q - n
Hence, we get that the nth term of the series is (p + q - n).
AND PLS CORRECT YOUR. QUESTION
WE HAVE NOT FIND 10TH TERM HERE, WE HAVE TO FIND NTH TERM TO ROBE IT.
HOPE IT IS HELPFUL TO YOU,
PLS MARK IT AS BRAINLIEST!!!!
mandeepkour29:
hello g
Answered by
2
I think that since ur to find 10 th term then it would be only like,p+q-10
If that's so then this's the answer...
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