if px =ax²+bx+c and a+b+c =0 then ine of the zeroes is
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Given p,q are the roots of ax^2 - bx + c=0
Then p+q=?
As we know p and q are the roots then
(x-p)(x-q) = 0
x^2-qx-px+pq=0
x^2-x(p+q)+pq=0
By given equation
a=1
b=(p+q)
c=pq
(p+q) =b/a
Then p+q=?
As we know p and q are the roots then
(x-p)(x-q) = 0
x^2-qx-px+pq=0
x^2-x(p+q)+pq=0
By given equation
a=1
b=(p+q)
c=pq
(p+q) =b/a
raju5:
tq
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