Question

if px = x^2-2√2x+1 then p(2√2) a)0 b)1 b) 4√2 c) 8√2+1​

Answer 1

$answer$

$px = x^2-2√2x+1$

$p(2 \sqrt{2} ) = {(2 \sqrt{2} )}^{2} - {(2 \sqrt{2}) }^{2} + 1$

=1

So option B is your answer.

Answer 2

Answer:

1

Step-by-step explanation:

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