Question

If px2+3x+q=0 has two real roots x=-1 and x=-2, find p-q

Answer 1

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px² + 3x + q = 0

Take x=1,

p×1² + 3×1 + q = 0

p + 3 +q = 0

p + q = -3 ------(1)

Take x=2,

p×2² + 3×2 + q = 0

4p + 6 + q = 0

4p + q = -6 -------(2)

p + q = -3 --------(1)

4p + q = -6 --------(2)

________________

-3p + 0 = 3

p = $\frac{-3}{3}$

p = -1

Substitute p = -1

p + q = -3

-1 + q = -3

q = -3 + 1

q = -2

Therefore,

p = -1

q = -2

Hope it helps you.

Answer 2

Answer:

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