Question

If px2 + qx + r = 0 has equal roots, value of r will be

Answer 1

i hope this answer helpful for us

Answer 2

Value of r is $\frac{q^2}{4p}$.

Given:

px² + qx + r = 0 has equal roots

To Find:

Value of r

Solution:

Given the equation px² + qx + r = 0, has equal roots.

Then Discriminant should be 0.

Therefore,

D = 0

b²-4ac = 0

where,

b = -q    

a = p  

c = r

⇒$(-q)^{2} - 4 * p * r = 0$

⇒$4 * p * r = q^{2}$

⇒$r = \frac{q^2}{4p}$

Therefore , value of r is $\frac{q^2}{4p}$.

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