Question

If Q(0, –1, –3) is the image of the point P in the plane 3x – y, 1.4z = 2 and R is the point (3, –1, –2), then the area (in square units) of ∆PQR is:
(A) √91/2
(B) 2√13
(C) √65/2
(D) √91/4

Answer 1

Step-by-step explanation:

If Q(0, –1, –3) is the image of the point P in the plane 3x – y, 1.4z = 2 and R is the point (3, –1, –2), then the area (in square units) of ∆PQR is:

(A) √91/2

(B) 2√13

(C) √65/2

(D) √91/4

Answer 2

Answer:

If Q(0, –1, –3) is the image of the point P in the plane 3x – y, 1.4z = 2 and R is the point (3, –1, –2), then the area (in square units) of ∆PQR is:

(A) √91/2 ✔✔

(B) 2√13

(C) √65/2

(D) √91/4