Math, asked by misskritimishra, 1 year ago

if Q (0,1) is equdistant from P(5,-3) and R(x,6) find the value of x .Also distances QR and PR

Answers

Answered by YasminGautam

Hey mate...

Here's the answer to your question...

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misskritimishra: don't understand

YasminGautam: I've added another photo in my answer

YasminGautam: Check it ouy

YasminGautam: out*

YasminGautam: Hope you'll understand

misskritimishra: please check out the formula u have written

misskritimishra: smajh me nahi a raha formula ke bad

Answered by rajputdeepti000

Answer:

Step-by-step explanation:

i hope this will help u

Attachments:

misskritimishra: where is the solution

rajputdeepti000: wait please

rajputdeepti000: if PQ = RQ

rajputdeepti000: then their square also equal therefor PQ2 =RQ2 wkt that distance formula root x2-x1 +y2-y1 PQ = RQ root (5-0)sq +(-3-1)sq =root 25+16 therefore PQ = root 41 lly for RQ root (x-0)sq+(6-1)sq there fore root Xsq +25

rajputdeepti000: now squaring both side we get PQsq = RQsq

rajputdeepti000: root 41 = root Xsq+25

rajputdeepti000: 41-25 = xsq

rajputdeepti000: 16 = Xsq therfore x = +-4

deeptirajput2233: Thanks your answer is almost perfect ❤

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if Q (0,1) is equdistant from P(5,-3) and R(x,6) find the value of x .Also distances QR and PR​

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if Q (0,1) is equdistant from P(5,-3) and R(x,6) find the value of x .Also distances QR and PR