Question

If Q( 0,1) is equidistant from P(5,-3) and R(x,6) , find the values of x .Also find the distance QR and PR. !please solve the que​

Answer 1

Explanation:

Q( 0,1) is equidistant from P(5,-3) and R(x,6)

QP= Q R

QP = √[ (5-0)^2 + (-3-1)^2]

=√[ 25 + 16]

= √41

= 6.40 units

QR = √[ (x-0)^2 + (6-1)^2]

= √ [ x^2 + 25]

QP= Q R

41=x^2 + 25

x^2 = 16

x = + or - 4

for x= 4 and x= -4 the QR = √41

Answer 2

Answer:

♠️ I HOPE HELP YOU ♠️

Explanation:

For x = 4 ____❤️

x = - 4 the QR = √ 41