Question

If q-1 ,q+3,3q-1 are in AP then quickly is a equal to

Answer 1

Step-by-step explanation:

$according \: to \: the \: principle \: of \: a.p. \\ q + 3 - (q - 1) = 3q - 1 - (q + 3) \\ q + 3 - q + 1 = 3q - 1 - q - 3 \\ 4 = 2q - 4 \\ 2q = 4 + 4 \\ 2q = 8 \\ q = \frac{8}{2} \\ q = 4$

Answer 2

Answer:

d = q = 4

Step-by-step explanation: