Physics, asked by Pathanjuned7283, 1 year ago

If Q=4v^3+3v^2 then the value of v for max Q is

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Answered by Anonymous
17
Hi !!!

For Q to be max d²Q / dv² must be = 0

{ d²Q / dv² }= 24v + 6

24v +6 = 0

v = - 1 / 4

d²Q / dv². is the second derivative of Q w.r.t v


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Answered by Anonymous
7
heya!!!!

here is ua answer:

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