Question

If Q (h,k) is the image of the point P(x,y,) war.t. the straight line ax+by+c =0, then (h-x): a = ( ky):5= 2(ax : by 1c):(a + b )and find the image of(1.-2) with respect to the straight line 2r-3y=5= 0​

Answer 1

Answer:

I think it is helpful

Step-by-step explanation:

2

h−1

=

−3

k+2

=

(2)

2

+(−3)

2

−2((2×1)−3(−2)+5)

2

h−1

=

−3

k+2

=

13

−2(13)

=−2

2

h−1

=−2

h=−3

−3

k+2

=−2

k=−8

∴point≡(−3,−8)