Math, asked by srikaryadav833, 4 months ago

If Q(h,k) is the image of the point P(x1,y1) what are the the straight line ax + by + c=0, then (h-x1): a = (K-y1,) :b = -2 ( ax1 + by1 + c): (a^2 + b^2)

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Answered by xXMarziyaXx
20

If Q(h,k) is the image of the point P(x1,y1) w.r.to the straight line ax+by+c=0then prove that (h-x1):a=(k-y1):b=-2(ax1+by1+c):a2+b2 or h-x1a=k-y1b=-2(ax1+by1+c)a2+b2 and find the image of (1,-2) w.r.t the straight line 2x-3y+5=0.

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