If q is a prime numbers, then prove that root q is an irrational number.
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Answer:
Step-by-step explanation:
If possible,let √q be a rational number.
also a and b is rational.
then,√q = a/b
on squaring both sides,we get,
(√q)²= a²/b²
→q = a²/b²
→b² = a²/q [p divides a² so,q divides a]
Let a= qr for some integer r
→b² = (qr)²/q
→b² = q²r²/q
→b² = qr²
→r² = b²/q [p divides b² so, q divides b]
Thus q is a common factor of a and b.
But this is a contradiction, since a and b have no common factor.
This contradiction arises by assuming √q a rational number.
Hence,√q is irrational.
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