Question

If Q lies between P and R and PR= 10 cm ,PQ=5 cm, what is the value of QR2

(a)15

(b)20

(c) 25

(d)35

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Answer 1

Answer:

Hello There,

This is your answer.

Step-by-step explanation:

PR = 10 cm

PQ = 5cm

QR = PR - PQ

= 10 - 5

= 5 cm

QR^2 = (5^2) cm^2

= 25 cm^2

QR^2 = 25 cm^2

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