If q(x)=x^3+3x^2+3x+1,find q(-2)+q(-3)+q(1/2)
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Answer:
Step-by-step explanation:
q(-2) = (-2)^3 + 3(-2)^2+ 3(-2) + 1
= -8 + 12 - 6 +1
= - 4 - 5
= 9
q(-3) = (-3)^3 + 3(-3)^2 + 3(-3) + 1
= -27 + 27 - 9 +1
= 0 - 9 + 1
= 8
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