Question

if q(x) = x raise to the power 3+ 3 raise to the power 2 + 3x + 1, then evaluate q(-2) + q(-3) + q (1/2). Please ARMY help me.​

Answer 1

Answer:

q(-2) = -4

q(-3) = -26

q(½) = 11⅝

Step-by-step explanation:

$q( - 2) = ( - 2) {}^{3} + 3 {}^{2} + 3\times-2 + 1$Solving, we have

$q( - 2) = - 4$

$q( - 3) = ( - 3 ) { }^{3} + 3 {}^{2} + 3 \times - 3 + 1$

Solving, we have

$q( - 3) = - 26$

$q( \frac{1}{2} ) = (\frac{1}{2})^{3} + 3 ^{2} + 3 \times\frac{1}{2} + 1$

Solving, we have

$q(\frac{1}{2}) = \frac{93}{8}$

$q( \frac{1}{2}) = 11\frac{5}{8}$

P. S- I'm not a BTS fan!

Hope you get this!