if QA is the perpendicular to CB , then find the length of CB
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assume Q is the centre of the circle
CB is cord
QAB is a triangle
let us assume that the A is the point is dividing the CB equally.
therefore CB = CA + AB and also CA = AB ( in length)
now,
by phythogoras theorem
QB² = AB² + QA²
5² = AB² + 3²
25 = AB² + 9
25 - 9 = AB²
16 = AB²
AB =√16
AB = 4
Since AB = CA
CA = 4
The length of CB = CA + AB
= 4 + 4
= 8
mohini200597:
thank u so much
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