Question

If QR = 35 and PR = 35 PM= 14 and QN= 10. prove that seg PQ || seg MN​

Answer 1

Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.

Given:

BC = 9, AB = 5, PQ = 6 and QR = 10.

$\text ∴\frac{A(△ABC)}{A(△PQR)} = \frac{AB×BC}{PQ×QR} = \frac{5×9}{6×10}= \frac{3}{4}$

Answer 2

Answer:

Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.

Given:

BC = 9, AB = 5, PQ = 6 and QR = 10.

\text ∴\frac{A(△ABC)}{A(△PQR)} = \frac{AB×BC}{PQ×QR} = \frac{5×9}{6×10}= \frac{3}{4}∴

A(△PQR)

A(△ABC)

=

PQ×QR

AB×BC

=

6×10

5×9

=

4

3

Step-by-step explanation:

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