Question

If quadratic equation :
(3a - 4)x^2 + (5b + 1) x-2 = 0
(4a + 3) x^2 - (6b - 5) x + 3 = 0
Having both roots common then find value of a and b

Answer 1

Answer:

if the roots are equal for any equation

then b^2-4ac = 0