Question

if quadratic equation kx²+2x+k=0 has two equal roots, then find the value of k​

Answer 1

Answer:

a=k b=2 c=k

Now

${b}^{2} - 4ac = 0$

$( {2})^{2} - 4(k)(k) = 0$

$4 - {4k}^{2} = 0$

${4k}^{2} = 4$

${k }^{2} = 1 \\ k = \sqrt{1} \\ k = 1$

Answer 2

Step-by-step explanation:

kx2+2x+k=0

As, roots are equal,

So, Discriminant, D=0

⟹22−4k2=0

⟹k2=1

Hence, k=−+1