Question

if quadrilateral ABCD is a parallelogram angle A =x° angle B =3x+20° find the value of x​

Answer 1

Answer:

Given:-

If the quadrilateral ABCD is a parallelogram ∠A = x° , ∠B = 3x + 20°, find the value of x°.

To Find:-

The value of "x".

Note:-

●》In parallelogram, opposites angles are equal and their sums makes 360° i.e. ∠A = ∠C, ∠B = ∠D and ∠A + ∠B + ∠C + ∠D = 360°.

●》For finding some unknown values like "x", known values needs to rearranged from its side to another and signs are also changed or not. For example - positive becomes negative ( signs are changed ), multiple becomes divisional ( signs are not change ).

To Find:-

$\huge\red{∠A = ∠C = x°, ∠B = ∠D = 3x + 20°}$

☆ According to note first point~

▪︎$∠A + ∠B + ∠C + ∠D = 360°$

▪︎$x° + 3x + 20° + x° + 3x + 20° = 360°$

▪︎$4x° + 20° + 4x° + 20° = 360°$

▪︎$8x° + 40° = 360°$

☆ According to note second point ( rearrangement )~

▪︎$8x° = 360° - 40°$

▪︎$8x° = 320°$

▪︎$x° = \frac{320}{8}$

☆ After doing division~

▪︎$x° = 40°$

$\huge\pink{x = 40°}$

Answer:-

Hence, the value of x = 40°.

:)