if quotient on dividing 3x cube plus 11x square plus 34x plus 106 ÷ x minus 3 is 3xsquare minus ax+b
find a,b and remainder
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Answer:
3x³+11x²+106÷x-3
q=3x²-ax+b
Step-by-step explanation:
so,remainder =286
a=-20
b=60
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