Question

 If r=1/3 and a=9 then find t7=?

1/81

1/82

1/71

1/72​

Answer 1

Answer:

$tn = a {r}^{n - 1}$

$t7 = 9 { (\frac{1}{3}) }^{7 - 1}$

$= t7 = \frac{9}{ {3}^{6} } = \frac{ {3}^{2} }{ {3}^{6} } = \frac{1}{ {3}^{4} }$

$= t7 = \frac{1}{81}$

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