Question

If R= 10x + 300 and C= 4x+1500, then
the break-even point is​

Answer 1

Set R(x) = C(x). Solve for x.

200x - 2x2 = -x2 + 10x + 7425

Move all the terms to the right side of the equation to make the left side equal to zero.

0 = x2 - 190x + 7425

Next, use the quadratic formula to solve for x:

x = (-b ± √(b2 - 4ac)) / 2a

where:

a = 1

b = -190

c = 7425