Question

if r=13 cm, and chord of circle's length 24 cm then___ is the distance between chord and centre.​

Answer 1

Answer:

Step-by-step explanation:

The radius is 13cm. Chords length is 24cm.

Draw a perpendicular from the centre to the chord bisecting the chord.

Let the radius be AB and the chord be CD.

Draw Am perpendicular to CD.

Now join AC and AD.

AC=AD=AB- all are radii

Then, using pythagoras theorem,

In triangle ACM,

Ac^2= CM^2+AM^2

13^2= 12^2+AM^2- perpendicular drawn from the centre bisects the chord into 2 equal parts

169= 144+ AM^2

169-144= AM^2

25= AM^2

Therefore, AM= square root of 25= 5cm

Thus, distance between the radius and the centre is 5cm

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