Question

If R=500omega, V=250 then find P

Answer 1

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Given ,

• Resistance = 500 ohm
• Potential difference = 250 volt

We know that ,

$\large \sf \fbox{R = \frac{ {(V)}^{2} }{P} }$

Substitute the known values , we get

$\sf \hookrightarrow 500 = \frac{ {(250)}^{2} }{p} \\ \\ \sf \hookrightarrow p = \frac{250 \times 250}{500} \\ \\ \sf \hookrightarrow p = \frac{25 \times 25}{5} \\ \\ \sf \hookrightarrow p = 5 \times 25 \\ \\ \sf \hookrightarrow p = 125 \: \: watt$

Hence , the required value of power is 125 watt

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Answer 2

Answer:

P = 125 W

Explanation:

Resistance=R= 500Ω=V/I

500=250/I

I= 250/500

I=1/2 A

P = VxI

P=250 x 1/2

P = 125 W