If r=8.0 ohm and the battery voltage vo=21.0v, what is the current in the 2r resistor?
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Given r=8 so 2r=2*8=16 ohm
V=Ir
21=I*16
I=21÷16
I=1.31 ohm
V=Ir
21=I*16
I=21÷16
I=1.31 ohm
Vanshsharma420:
sorry I typed ohm in place of ampere
sorry I typed ohm in place of ampere
Sorry I typed ohm in place of ampere
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