Question

If r and s are the roots of ax2+bx+c=0 then the value of [r/s-s/r]2

Answer 1

Answer:

If r and s are the roots of the equation x^2+bx+c=0, where b and c are constants, is rs<0?

Viete's theorem states that for the roots and of a quadratic equation :

AND .

Thus according to the above . So, we are basically asked whether .

(1) b<0. Not sufficient.

(2) c<0. Directly answers the question. Sufficient.

Step-by-step explanation:

if u like it then follow me and make me as a brainliest answer.