If r is positive r>l, it is convenient to
write sn= a(r^n-1) ÷r-1
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Answer:
Yes, this is a convenient solution.
Step-by-step explanation:
Sum of Geometric series is given by
S=a+a*r+a*(r^2)+to+a*(r^(n-1))
Multiplying both sides with r,
(r*S)=a*r+a*(r^2)+to+a*(r^(n-1))+a*(r^n)
since r>1,
(r*S)>S
So,
(r*S)-S=a*(r^n)-a
or, S(r-1)=a*(r^n-1)
or, S= a*(r^n-1)/(r-1)
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