Physics, asked by doggalashankaraiah, 11 months ago

If R is radius of the earth, the height above the surface of the earth where the weight of a body is 36% less than its weight on the surface of the earth is

Answers

Answered by Defsoul
1

Answer:

Explanation:

We know, g = GM / R2  

gh ÷ g = GM ÷ R + h2  ×  R2 ÷ GM

or, 1÷4g  /g = R2 ÷ (R + h)2

  R + h ÷ R = 2/1

  1 + h÷R = 2

  h÷R = 1

 h=R

Similar questions