Question

If R is the radius of earth and g is the acceleration
due to gravity on the earth's surface. Then mean
density of earth is​

Answer 1

$\longrightarrow\sf{g=\dfrac{GM}{R^2}}$

$\longrightarrow\sf{g=\dfrac{G\cdot \rho\cdot\dfrac{4}{3}\pi R^3}{R^2}}$

$\longrightarrow\sf{g=\dfrac{4}{3}\pi\rho RG}$

$\longrightarrow\sf{\underline{\underline{\rho=\dfrac{3g}{4\pi RG}}}}$