If R is the radius of earth and g is the acceleration due to gravity on the Earth's surface, the mean
density of the Earth is
a)4πG÷3gR
b)3πR÷4gG
c)3g÷4πRG
d)πRg÷12G
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Question :
If R is the radius of the earth and g the acceleration due to gravity on the earth’s surface the mean density of the earth is = ………. A [4πG / 3gR] B [3πR / 4gG] C [3g / 4πRG] D [πRG / 12g]
Answer :
Correct option: C [3g / 4πRG]Explanation:g = [G ∙ M / R2]Mass of earth = volume × DensityM = 4/3πR3ρg = G × 1/R2 × 4/3πR3ρ = 4/3GπρRhence ρ = [3g / 4πGR]
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