Question

if R is the radius of the earth the height above the surface of the Earth where the weight of the body is 36% less than its value on the earth surface​

Answer 1

Answer:

A planet has twice the density of the earth but the acceleration due to gravity on its surface is same as that on the surface of the earth. If r is radius of the earth, then that of the planet is

Answer 2

Answer:

h= R/4

Explanation:

Lets take mass of the body = m

Mass of the earth =M

The weight of the body = m g

$mg=G\dfrac{Mm}{R^2}$   ---------1

Lets take at distance h weight is 36 %.

So new wight = (1 - 0.36) m g

$0.64mg=G\dfrac{Mm}{(R+h)^2}$           ------------2

From equation 1 and 2

$0.64G\dfrac{Mm}{R^2}=G\dfrac{Mm}{(R+h)^2}$

$0.64\dfrac{1}{R^2}=\dfrac{1}{(R+h)^2}$

0.64 (R+h)² = R²

0.8 (R+h) = R

0.8 R + 0.8 h= R

0.8 h= 0.2 R

h= R/4