Question

..
If R is the radius of the sphere in the close packed
arrangement and r is the radius of the tetrahedral void,
then:
(a) R=0.414
(b) r=0.224 R
(C) R = 0.225 r (d) r=0.414 R​

Answer 1

Answer:

c) R=0.225 r

Explanation:

if R is the radius of the sphere in the close packed arrangement and r is the radius of the tetrahedral void, then the solution for R will be

R=0.225 r