Physics, asked by gargnirmal78, 11 months ago

If R is the range of a projectile on a horizontal plane and h its
maximum height, the maximum horizontal range with the
same velocity of projection is: a) 2h
(b) R² / 8h
(c) 2R+h2 /8R. (d) 2h + R2/8h

Answers

Answered by gyaneshwarsingh882
0

Answer:

Explanation:

R=  

g

16sin2θ

h=  

2g

16sin  

2

θ

 

R

h

=  

g

16sin  

2

θ

×  

16sinθ

g

=  

4

1

tanθ

=tanθ=  

R

4h

 

X=  

R  

2

+(4h)  

2

 

 

sinθ=  

R  

2

+16h  

2

 

 

4h

 

R  

max

=  

16h  

2

 

2h(R  

2

+16h  

2

)

 

R  

max

=  

8h

R  

2

 

+2h

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