If R makes an angle ß with then tan |
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Given that the angle between
a
and
b
is θ
Since (a + b ) makes an angle of α with
, hence
⟹tan α=
(a+bcos θ)
bsin θ
Similarly, ( a − b ) makes an angle of β with a , Hence
⟹tan β=
(a−bcos θ)
bsin θ
Adding both the equation we get,
⟹tan α+tan β=
(a+bcos θ)
bsin θ + (a−bcos θ)bsin θ
⟹tan α+tan β=bsinθ[
(a+bcosθ)
1
+
(a−bcosθ)1 ]
⟹tan α+tan β=bsinθ[
(a+bcosθ)(a−bcosθ)
(a−bcosθ+a+bcosθ)
]
⟹tan α+tan β=
a²−b²cos²θ
2absinθ
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