Question

If R= P + and R=1P+Q| find the angle between P and Q.​

Answer 1

When,  

P

+  

Q

​  

=  

R

 or  

P

−  

R

=−  

Q

​  

 

(  

P

−  

R

).(  

P

−  

R

)=(−  

Q

​  

).(−  

Q

​  

)

P  

2

+R  

2

−2PRcosθ  

1

​  

=Q  

2

 

cosθ  

1

​  

=1/2  (as P=Q=R)

θ  

1

​  

=60  

0

 

When,  

P

+  

Q

​  

+  

R

=0 or  

P

+  

R

=−  

Q

​  

 

(  

P

+  

R

).(  

P

+  

R

)=(−  

Q

​  

).(−  

Q

​  

)

P  

2

+R  

2

+2PRcosθ  

2

​  

=Q  

2

 

cosθ  

2

​  

=−1/2  (as P=Q=R)

θ  

2

​  

=120  

0

 

Thus, θ  

1

​  

=  

2

θ  

2

​  

 

​

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Answer 2

Explanation:

$\huge{ \purple{b}r\red{a} \green{i} \pink{n} \orange{l} \purple{i} \green{s}t}\\</p><p> \huge{ \purple{p}\red{l} \green{e} \pink{a} \orange{s} \purple{e} }$

Answer:

sin(90)=1

Step-by-step explanation:

sum of three angle of triangle =180

P+Q+R =180

As Q = 90

P+R=180-Q

P+R=180-90

P+R=90

sin(90)=1

https://brainly.in/question/11965406

If a ∆ PQR is right angled at Q, then find the value of sin(P+R ...