Question

If R=P×Q,show that 4R(3P+6Q )=0​

Answer 1

Answer:

Given p, q, r are positive (hence non-zero) integers. And we need to find the value of p + q + r.

Considering statement 1:

7p × 5q = 175 and 4p = r

7p × 5q = (7*1)*(5*5)

⇒ p = 1 and q = 5

and r = 4(1) = 4

⇒ p + q + r = 10

Since we are getting a definite answer from above statement, statement 1 itself is sufficient to provide the answer.

Considering statement 2:

r is 200% more than p and 100% more than q, where p + r is a single digit number

⇒ r = p + 200p/100 = 3p

and r = q + 100q/100 = 2q

⇒ p + r = p + 3p = 4p

Now, 4p is either 4 or 8

⇒ p = 1 or 2

Hence, r = 3p = 3 or 6

And r = 2q gives: q = 1.5 or 3. However, since these are positive integers, q = 3 (p cannot be 1).

⇒ p + q + r = 2 + 6 + 3 = 11

Since we are getting a definite answer from above statement, statement 2 itself is sufficient to provide the answer.

As statement 1 and 2 both alone are sufficient to provide the answer.

Explanation: