if R:R is defined by f(x)= |x|-5 then the range of f is
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Step-by-step explanation:
ANSWER
For a function f(x) to be invertible, the function must be one-one and onto.
The range of f(x)=∣x∣ is [0,∞), while the co-domain of f(x) is given as R. Hence f(x) is not onto.
Also, since f(x)=f(−x), f(x) is also not one-one in its domain.
Hence, f(x) is not invertible, ie, the function f
−1
(x) does not exist.
Option C is the right answer.
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