Math, asked by anjaligontu, 2 days ago

If r + s = t and x = y, then the true statement is A) r + S - X = y-t B) r + S-t = x + y C) r + s + x = t + y D) r + s + t = x - y​

Answers

Answered by kajalkushwah369
1

Answer:

c).r + s + x = t + y

Step-by-step explanation:

hope it will help you

Answered by payalchatterje
0

Answer:

r + s + x = t + y is the correct answer.

So, option c is the correct answer.

Step-by-step explanation:

Given,

r + s = t ....(1) and x = y.....(2)

From equation (1),

r + s = t \\ r + s - t = 0.....(3)

and

x = y \\ y-x = 0.....(4)

From equation (3) and (4),

r + s - t = -x +y

r + s + x = y + t

So,this is a correct answer.

This is a Mathematics problem.

Some important Mathematics formulas:

{(x + y)}^{2}  =  {x}^{2}  + 2xy +  {y}^{2} \\  {(x  -  y)}^{2}  =  {x}^{2}   -  2xy +  {y}^{2} \\  {(x  + y)}^{3}  =  {x}^{3}  + 3 {x}^{2} y + 3x {y}^{2}  +  {y}^{3}  \\   {(x   -  y)}^{3}  =  {x}^{3}   -  3 {x}^{2} y + 3x {y}^{2}   -  {y}^{3} \\  {x}^{3}  +  {y}^{3}  =  {(x  +  y)}^{3}  - 3xy(x + y) \\ {x}^{3}   -  {y}^{3}  =  {(x   -   y)}^{3}   +  3xy(x  -  y) \\  {x}^{2}  -  {y}^{2}  = (x + y)(x - y) \\    {x}^{2}  +  {y}^{2}  =  {(x - y)}^{2}   + 2xy \\ {x}^{2}   -  {y}^{2}  =  {(x   + y)}^{2}  - 2xy \\  {x}^{3}  -  {y}^{3}  = (x - y)( {x}^{2}  + xy +  {y}^{2} ) \\ {x}^{3}   +   {y}^{3}  = (x + y)( {x}^{2}   -  xy +  {y}^{2} )

Two more important Mathematics problem:

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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