If r square =pq show that p:q is the duplicate ratio of (p r):(q r)
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Given
r^2=pq,
(pr) :(qr)
(First open brackets.)
pr:qr
(Here in both terms 'r' is common, then it will be canceled.)
p:q
therefore pr:qr is the duplicate ratio of p:q.
Hence proved.
r^2=pq,
(pr) :(qr)
(First open brackets.)
pr:qr
(Here in both terms 'r' is common, then it will be canceled.)
p:q
therefore pr:qr is the duplicate ratio of p:q.
Hence proved.
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