Question

if r value is less than 1 then finding the sum of infinite geometric progression is

Answer 1

HOLA friend!!
Rajdeep here...

If a is the first term and r is the common ratio, and n is the number of terms (here, infinite)....
And r is less than 1 (r<1),
Refer to the picture to know about the formula....

Answer 2

Answer:

S = a/ 1 - r

Step-by-step explanation:

In geometric progression,

If a is the first term and r is the common ratio, and n is the number of terms

And r is less than 1 (r < 1)

Sum of the geometric progression finite numbers

S = a ( 1 - r^n)/ 1 - r

Geometric progression of infinite number, S = a/ 1 - r