Math, asked by rsaroj491, 2 months ago

if R=x^i+yj+2k,then prove that
1.div(r n R)=(n+3)r
2.curl(r n R)=0

Answers

Answered by sanketparida15

0

Answer:

4738+3&;₹)₹836839₹:":)₹/@&#6839:'-₹(3875₹)3/)

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