Math, asked by Nishant1976, 9 months ago

If R = { (x,y) : x and y are integers and x^2 +y^2 =64}, is a relation on Z, write in roster form

Answers

Answered by shivankprajapati
7

Step-by-step explanation:

We have, R2 = {(x, y) | x and y are integers and x2 + y2 – 64}

Clearly, x2 = 0 and y2 = 64 or x2 = 64 and y2 = 0

x = 0 and y = ±8

or x = ±8 and y = 0

R2 = {(0, 8), (0, -8), (8,0), (-8,0)}

Answered by ajajit9217
0

Answer:

The given relation in roster from is {(0, 8) , (0, -8) , (8, 0) , (-8, 0)}

Step-by-step explanation:

Given relation is R = {(x, y): x, y are integers and x² + y² = 64}

We need to write this in roster form.

Therefore, we have to find the values of x and y for which

x² + y² = 64 holds true.

x  0   0    8    -8  

y  8   -8   0    0

Therefore, (x, y) = (0, 8) , (0, -8) , (8, 0) , (-8, 0)

Therefore, the given relation in roster from is

{(0, 8) , (0, -8) , (8, 0) , (-8, 0)}

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