Question

If r1=2, r2=3, r3=6, r=1
Prove a=3, b=4, C=5​

Answer 1

Answer:

We have r

1

​

=

s−a

Δ

​

=2⇒s=a+

2

Δ

​

.......(2)

similarly s=b+

3

Δ

​

........(2)

and s=c+

6

Δ

​

.........(3)

Now add all 3 equations

⇒3s=2s+Δ⇒s=Δ

Now using Heron's formula Δ=

s(s−a)(s−b)(s−c)

​

⇒Δ=

Δ⋅

2

Δ

​

⋅

3

Δ

​

⋅

6

Δ

​

​

=

6

Δ

2

​

⇒Δ=6, hence by (1) a=

2

Δ

​

=3

Step-by-step explanation:

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Answer 2

Answer:

see in the above picture for clarity