If R1=4 and R2=4. The potential difference is 6
In the given circuit, calculate :
(a) the total resistance of the circuit
(b) the current through the circuit, and
(c) the potential difference across R, and R,
Answers
Answered by
1
Answer:
r1=4
r2=4
v=6v
Explanation:
(a)R's=r1+r2=4+4=8ohms
(b) v=ir
i=v÷r
I=6÷8=0.75A
THANK YOU MARK BRILLIANT
Answered by
2
Answer:
Explanation:V=6 V
R1=4
R2=4
Now if it is in a series arrangement then the total resistance would be
4+4=8 ohm
In parallel arrangement
1/4+1/4=1/2
So the resistance would be its reciprocal i. e. 2 ohm
Therefore I in series=6/8=3/4=0.75A
I in parallel =6/2=3A
So P. D in series :
R1 P. D= 6/2=3V
IT IS BECAUSE THE P. D GETS DISTRIBUTED IN A RATIO THAT IS SAME AS THE RATIO OF THE TWO RESISTANCES. SO THE RATIO WOULD BE 1:1
SO THE P. D IN R2 IS ALSO 3V
IN PARALLEL THE P. D S SAME IN BOTH THE RESISTANCES SO THE P. D IS 6V.
PLZ MARK THE BRAINLIEST
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