Science, asked by raghav0429236464, 11 months ago

If R1=4 and R2=4. The potential difference is 6
In the given circuit, calculate :
(a) the total resistance of the circuit
(b) the current through the circuit, and
(c) the potential difference across R, and R,

Answers

Answered by prathibhakiran4
1

Answer:

r1=4

r2=4

v=6v

Explanation:

(a)R's=r1+r2=4+4=8ohms

(b) v=ir

i=v÷r

I=6÷8=0.75A

THANK YOU MARK BRILLIANT

Answered by dsaha25
2

Answer:

Explanation:V=6 V

R1=4

R2=4

Now if it is in a series arrangement then the total resistance would be

4+4=8 ohm

In parallel arrangement

1/4+1/4=1/2

So the resistance would be its reciprocal i. e. 2 ohm

Therefore I in series=6/8=3/4=0.75A

I in parallel =6/2=3A

So P. D in series :

R1 P. D= 6/2=3V

IT IS BECAUSE THE P. D GETS DISTRIBUTED IN A RATIO THAT IS SAME AS THE RATIO OF THE TWO RESISTANCES. SO THE RATIO WOULD BE 1:1

SO THE P. D IN R2 IS ALSO 3V

IN PARALLEL THE P. D S SAME IN BOTH THE RESISTANCES SO THE P. D IS 6V.

PLZ MARK THE BRAINLIEST

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