Question

If R1 = (5.0 ± 0.1) Ώ and R2 = (5.0 ± 0.2) Ώ. Determine (i) R = R1+R2 ( ii) R = R1R2 / (R1+R2) and the percentage error in both cases.

Answer 1

Answer:

ANSWER

Two resistors, R

1

andR

2

are connected in parallel.

We know,

R

e

1

=

R

1

1

+

R

2

1

Then R

e

=

R

1

+R

2

R

1

R

2

=

50+100

50×100

=

150

5000

=

3

100

Now, Parallel Connection error:

=

(R

1

+R

2

)

2

R

1

2

(dB)+R

2

2

(dA)

=

150

2

50

2

(3)+100

2

(2)

=

150×150

7500+20000

=

9

11

Relative Error =

(100/3)

(11/9)

=0.03666